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Find Output Of Program

Question 1 :

What will be the output of the program?

#include
int main()
{
    float a=0.7;
    if(a < 0.7)
        printf("C\n");
    else
        printf("C++\n");
    return 0;
}


A). C
B). C++
C). Compiler error
D). Non of above
Answer : Option A

Explanation :

if(a < 0.7) here a is a float variable and 0.7 is a double constant. The float variable a is less than double constant 0.7. Hence the if condition is satisfied and it prints 'C'

Example:

#include
int main()
{
    float a=0.7;
    printf("%.10f %.10f\n",0.7, a);
    return 0;
}

Output: 0.7000000000 0.6999999881


Question 2 :

What will be the output of the program?

#include
int main()
{
    float *p;
    printf("%d\n", sizeof(p));
    return 0;
}


A). 2 in 16bit compiler, 4 in 32bit compiler
B). 4 in 16bit compiler, 2 in 32bit compiler
C). 4 in 16bit compiler, 4 in 32bit compiler
D). 2 in 16bit compiler, 2 in 32bit compiler
Answer : Option A

Explanation :

sizeof(x) returns the size of x in bytes.
float *p is a pointer to a float.

In 16 bit compiler, the pointer size is always 2 bytes.
In 32 bit compiler, the pointer size is always 4 bytes.


Question 3 :

What will be the output of the program?

#include
int main()
{
    float fval=7.29;
    printf("%d\n", (int)fval);
    return 0;
}


A). 0
B). 0.0
C). 7.0
D). 7
Answer : Option D

Explanation :

printf("%d\n", (int)fval); It prints '7'. because, we typecast the (int)fval in to integer. It converts the float value to the nearest integer value.


Question 4 :

What will be the output of the program?

#include
#include
int main()
{
    printf("%f\n", sqrt(36.0));
    return 0;
}


A). 6.0
B). 6
C). 6.000000
D). Error: Prototype sqrt() not found.
Answer : Option C

Explanation :

printf("%f\n", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000).

Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number.


Question 5 :

What will be the output of the program?

#include
#include
int main()
{
    printf("%d, %d, %d\n", sizeof(3.14f), sizeof(3.14), sizeof(3.14l));
    return 0;
}


A). 4, 4, 4
B). 4, 8, 8
C). 4, 8, 10
D). 4, 8, 12
Answer : Option C

Explanation :

sizeof(3.14f) here '3.14f' specifies the float data type. Hence size of float is 4 bytes.
sizeof(3.14) here '3.14' specifies the double data type. Hence size of float is 8 bytes.
sizeof(3.14l) here '3.14l' specifies the long double data type. Hence size of float is 10 bytes.
Note: If you run the above program in Linux platform (GCC Compiler) it will give 4, 8, 12 as output. If you run in Windows platform (TurboC Compiler) it will give 4, 8, 10 as output. Because, C is a machine dependent language.