General Questions

Question 6 :

We want to round off x, a float, to an int value, The correct way to do is


A). y = (int)(x + 0.5)
B). y = int(x + 0.5)
C). y = (int)x + 0.5
D). y = (int)((int)x + 0.5)
Answer : Option A

Explanation :

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.
y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)
Example:

#include 
int main ()
{
  float x = 3.6;
  int y = (int)(x + 0.5);
  printf ("Result = %d\n", y );
  return 0;
}
Output:
Result = 4.


Question 7 :

The binary equivalent of 5.375 is


A). 101.101110111
B). 101.011
C). 101011
D). None of above
Answer : Option B

Question 8 :

A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?


A). ABCD
B). DCBA
C). 0xABCD
D). Depends on big endian or little endian architecture
Answer : Option D

Question 9 :

What will you do to treat the constant 3.14 as a float?


A). use float(3.14f)
B). use 3.14f
C). use f(3.14)
D). use (f)(3.14)
Answer : Option B

Explanation :

Given 3.14 is a double constant.
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)


Question 10 :

Which of the following statement obtains the remainder on dividing 5.5 by 1.3 ?


A). rem = (5.5 % 1.3)
B). rem = modf(5.5, 1.3)
C). rem = fmod(5.5, 1.3)
D). Error: we can't divide
Answer : Option C

Explanation :

fmod(x,y) - Calculates x modulo y, the remainder of x/y.
This function is the same as the modulus operator. But fmod() performs floating point divisions.
Example:

#include 
#include 
int main ()
{
  printf ("fmod of 5.5 by 1.3 is %lf\n", fmod (5.5, 1.3) );
  return 0;
}

Output:
fmod of 5.5 by 1.3 is 0.300000